Find the z eros of the func tion. E nter the solutio ns fro m least to gr eatest. f(x)=(x-10)^2-49 lesser x= greater x=

To find the zeros of the function $f(x) = (x-10)^2 - 49$, we need to set the function equal to zero and solve for $x$.<br /><br />$(x-10)^2 - 49 = 0$<br /><br />Expanding the square term, we have:<br /><br />$(x-10)^2 = 49$<br /><br />Taking the square root of both sides, we get:<br /><br />$x-10 = \pm 7$<br /><br />Solving for $x$, we have:<br /><br />$x = 10 \pm 7$<br /><br />Therefore, the solutions are:<br /><br />$x = 10 - 7 = 3$ (lesser $x$)<br /><br />$x = 10 + 7 = 17$ (greater $x$)<br /><br />So, the zeros of the function are $x = 3$ and $x = 17$.