f(x)=x^2+5 f(1)=1^2+5=6 f(3)=3^2+5=14

The function $f(x)$ is defined as $f(x)=x^{2}+5$. To find $f(1)$, we substitute $x=1$ into the function, which gives us $f(1)=1^{2}+5=6$. Similarly, to find $f(3)$, we substitute $x=3$ into the function, which gives us $f(3)=3^{2}+5=14$.