Pergunta
Subtract the rational expressions. (2)/(4a-3)-(10)/(2a-1)
Solução
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VictorMestre · Tutor por 5 anos
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To subtract the rational expressions, we need to find a common denominator. The least common multiple (LCM) of the denominators $4a-3$ and $2a-1$ is $(4a-3)(2a-1)$. We can rewrite each fraction with the common denominator and then subtract the numerators.<br /><br />$\frac {2}{4a-3}-\frac {10}{2a-1}$<br /><br />$= \frac {2(2a-1)}{(4a-3)(2a-1)} - \frac {10(4a-3)}{(4a-3)(2a-1)}$<br /><br />$= \frac {4a-2 - 40a + 30}{(4a-3)(2a-1)}$<br /><br />$= \frac {-36a + 28}{(4a-3)(2a-1)}$<br /><br />Therefore, the result of the subtraction is $\frac {-36a + 28}{(4a-3)(2a-1)}$.
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