1- Write in the form of powers of 10: (2 pts) 10^0= 10^2times 10^3= 101 10^1= (10^4times 10^2)^3= 2- Write in the form of one power (4 pts) 2^2times 2^4= 5^3times 125^2= ..................................................................................... (2^2)^3times 16= ...................................................................... 9^3times 3^2= .................................................................................... 1- Perform: (Show your work step by step). (2 pts) (9-2times 4)^5-7times 2^2+(5-3)^2= .................................. ......................................... ......................................

Question

Pergunta

1- Write in the form of powers of 10: (2 pts) 10^0= 10^2times 10^3= 101 10^1= (10^4times 10^2)^3= 2- Write in the form of one power (4 pts) 2^2times 2^4= 5^3times 125^2= ..................................................................................... (2^2)^3times 16= ...................................................................... 9^3times 3^2= .................................................................................... 1- Perform: (Show your work step by step). (2 pts) (9-2times 4)^5-7times 2^2+(5-3)^2= .................................. ......................................... ......................................

Answer 1

1- Write in the form of powers of 10: (2 pts) $10^{0}=1$ $10^{2}\times 10^{3}=10^{5}$ $10^{1}=10$ $(10^{4}\times 10^{2})^{3}=10^{18}$ 2- Write in the form of one power (4 pts) $2^{2}\times 2^{4}=2^{6}$ $5^{3}\times 125^{2}=5^{7}$ $(2^{2})^{3}\times 16=2^{10}$ $9^{3}\times 3^{2}=3^{7}$ 1- Perform: (Show your work step by step). (2 pts) $(9-2\times 4)^{5}-7\times 2^{2}+(5-3)^{2}$ $=(9-8)^{5}-7\times 4+(5-3)^{2}$ $=1^{5}-28+2^{2}$ $=1-28+4$ $=-23$

Pergunta

Solução

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