Factor the quadratic equation below. 9r^2-5r-10 9r(r-3)(r+2) 9r(r+3)(r+2) r(r-3)(r+2) Cannot be factored

To factor the quadratic equation $9r^2 - 5r - 10$, we need to find two binomials that multiply together to give us the original quadratic expression.

First, let's rewrite the quadratic equation in standard form:
$$9r^2 - 5r - 10$$

We are looking for two numbers that multiply to $9 \times -10 = -90$ and add up to $-5$.

The pair of numbers that satisfy these conditions are $9$ and $-10$, because:
$$9 \times (-10) = -90$$
$$9 + (-10) = -1$$

However, we need the sum to be $-5$, not $-1$. So, we need to find another pair of factors.

After checking possible pairs, we find that:
$$10 \times (-9) = -90$$
$$10 + (-9) = 1$$

This still doesn't give us the correct sum. Let's try another approach using the quadratic formula to find the roots and then factorize.

The quadratic formula is given by:
$$r = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$$

For the quadratic equation $9r^2 - 5r - 10$, $a = 9$, $b = -5$, and $c = -10$.

Plugging in these values:
$$r = \frac{-(-5) \pm \sqrt{(-5)^2 - 4 \cdot 9 \cdot (-10)}}{2 \cdot 9}$$
$$r = \frac{5 \pm \sqrt{25 + 360}}{18}$$
$$r = \frac{5 \pm \sqrt{385}}{18}$$

Since the discriminant ($\sqrt{385}$) is not a perfect square, the quadratic does not factor neatly into rational binomials.

Therefore, the correct answer is:
$$\boxed{\text{Cannot be factored}}$$