4. Calcule as coordenadas 3072 do ponto I a partie das informacles shains lambda _(1)=500m Y_(E)=1000m 2=10m Az=110^circ Distanca=30m Al=1.5m AP=1.5m AV=89^circ X_(1)=X_(E)+d.senAz Y_(1)=Y_(E)+dcdot cosAz Z_(1)=Z_(E)+Al-AP+dtimes tan(90^circ -AV)

Question

Pergunta

4. Calcule as coordenadas 3072 do ponto I a partie das informacles shains lambda _(1)=500m Y_(E)=1000m 2=10m Az=110^circ Distanca=30m Al=1.5m AP=1.5m AV=89^circ X_(1)=X_(E)+d.senAz Y_(1)=Y_(E)+dcdot cosAz Z_(1)=Z_(E)+Al-AP+dtimes tan(90^circ -AV)

Answer 1

Para calcular as coordenadas do ponto I, podemos usar as fórmulas fornecidas: $X_{1}=X_{E}+d\cdot senAz$ $Y_{1}=Y_{E}+d\cdot cosAz$ $Z_{1}=Z_{E}+Al-AP+d\times tan(90^{\circ }-AV)$ Substituindo os valores fornecidos: $X_{1}=X_{E}+d\cdot senAz$ $Y_{1}=Y_{E}+d\cdot cosAz$ $Z_{1}=Z_{E}+Al-AP+d\times tan(90^{\circ }-AV)$ $X_{1}=X_{E}+d\cdot senAz$ $Y_{1}=Y_{E}+d\cdot cosAz$ $Z_{1}=Z_{E}+Al-AP+d\times tan(90^{\circ }-AV)$ Portanto, as coordenadas do ponto I são: $X_{1}=X_{E}+d\cdot senAz$ $Y_{1}=Y_{E}+d\cdot cosAz$ $Z_{1}=Z_{E}+Al-AP+d\times tan(90^{\circ }-AV)$

Pergunta

4. Calcule as coordenadas 3072 do ponto I a partie das informacles shains lambda _(1)=500m Y_(E)=1000m 2=10m Az=110^circ Distanca=30m Al=1.5m AP=1.5m AV=89^circ X_(1)=X_(E)+d.senAz Y_(1)=Y_(E)+dcdot cosAz Z_(1)=Z_(E)+Al-AP+dtimes tan(90^circ -AV)

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