MinZ=100X_(1)+800X_(2) or,+2 x>12 2x+2 x>s 4x+1 in z 74 X_(1),X_(2)geqslant 0

The correct answer is:<br /><br />$MinZ=100X_{1}+800X_{2}$<br /><br />This is a linear programming problem where the objective is to minimize the value of Z, which is a linear combination of the decision variables $X_{1}$ and $X_{2}$. The constraints are given by the inequalities $2x > 12$, $2x + 2x > s$, and $4x + 1 \leq 24$. The decision variables $X_{1}$ and $X_{2}$ are non-negative.