What is the equation in slope-intercept form of the line that passes through the points (-26,-11) and (39,34)

To find the equation of the line in slope-intercept form that passes through the points $(-26,-11)$ and $(39,34)$, we need to follow these steps:<br /><br />1. Calculate the slope of the line using the formula:<br /> Slope = (y2 - y1) / (x2 - x1)<br /><br /> Substituting the given points:<br /> Slope = (34 - (-11)) / (39 - (-26))<br /> Slope = 45 / 65<br /> Slope = 9 / 13<br /><br />2. Use the slope-intercept form of the equation of a line:<br /> y = mx + b<br /><br /> Where:<br /> m = slope<br /> b = y-intercept<br /><br />3. Substitute the slope and one of the given points into the equation to solve for the y-intercept:<br /> -11 = (9/13)(-26) + b<br /> -11 = -18 + b<br /> b = -11 + 18<br /> b = 7<br /><br />4. Write the final equation of the line in slope-intercept form:<br /> y = (9/13)x + 7<br /><br />Therefore, the equation of the line in slope-intercept form that passes through the points $(-26,-11)$ and $(39,34)$ is:<br />y = (9/13)x + 7