the equation of the circle centered at the origin and passing through the point (-3,0) square

The equation of a circle centered at the origin is given by \(x^2 + y^2 = r^2\), where \(r\) is the radius of the circle.<br /><br />Given that the circle passes through the point \((-3,0)\), we can use the distance formula to find the radius. The distance between the origin and the point \((-3,0)\) is 3 units.<br /><br />Therefore, the equation of the circle is \(x^2 + y^2 = 3^2\), which simplifies to \(x^2 + y^2 = 9\).