Pergunta

(2) Resolva as expressōes numéricas , aplicando as regras de s a) -9+7= __ b) +4+6=underline ( ) c) +12+(-12)=underline ( ) d) -7-(+10)=underline ( ) e) bigcirc +(-8)=underline ( ) f) -(-15)-(-16)=underline ( ) g) -11-9=underline ( ) h) -(-18)+(-22)=underline ( ) i) 12-(-4)+(-7)= __ j) -7+(+10)-(+5)=underline ( ) k) -22+(+15)+(-8)-(-16)-(+13)=underline ( ) 1) -(10+8)+(-15+33)-(-1+8)-(-17+10)=underline ( )
Solução

4.2288 Voting

Luciana MariaMestre · Tutor por 5 anos
Responder
a) -9+7=-2
b) +4+6=10
c) +12+(-12)=0
d) -7-(+10)=-17
e) \bigcirc +(-8)=\bigcirc -8
f) -(-15)-(-16)=15+16=31
g) -11-9=-20
h) -(-18)+(-22)=18-22=-4
i) 12-(-4)+(-7)=12+4-7=9
j) -7+(+10)-(+5)=-7+10-5=-2
k) -22+(+15)+(-8)-(-16)-(+13)=-22+15-8+16-13=-8
l) -(10+8)+(-15+33)-(-1+8)-(-17+10)=-(18)+(-15+33)-(-7)-(-7)=-18+18+7+7=14
b) +4+6=10
c) +12+(-12)=0
d) -7-(+10)=-17
e) \bigcirc +(-8)=\bigcirc -8
(Note: The symbol \bigcirc
is not defined in the question, so the answer cannot be determined.)
f) -(-15)-(-16)=15+16=31
g) -11-9=-20
h) -(-18)+(-22)=18-22=-4
i) 12-(-4)+(-7)=12+4-7=9
j) -7+(+10)-(+5)=-7+10-5=-2
k) -22+(+15)+(-8)-(-16)-(+13)=-22+15-8+16-13=-8
l) -(10+8)+(-15+33)-(-1+8)-(-17+10)=-(18)+(-15+33)-(-7)-(-7)=-18+18+7+7=14
Clique para avaliar: