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The length of a rectangle is five times its width. If the area of the rectangle is 180yd^2 , find its perimete yd square square

Pergunta

The length of a rectangle is five times its width.
If the area of the rectangle is 180yd^2
, find its perimete
yd
square 
square

The length of a rectangle is five times its width. If the area of the rectangle is 180yd^2 , find its perimete yd square square

Solução

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GustavoMestre · Tutor por 5 anos

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To find the perimeter of the rectangle, we first need to determine the length and width of the rectangle.<br /><br />Given that the length of the rectangle is five times its width, we can represent the length as 5w and the width as w.<br /><br />The area of the rectangle is given as 180 square yards. The formula for the area of a rectangle is length × width. So, we can set up the equation:<br /><br />5w × w = 180<br /><br />Simplifying the equation, we get:<br /><br />5w^2 = 180<br /><br />Dividing both sides by 5, we have:<br /><br />w^2 = 36<br /><br />Taking the square root of both sides, we find:<br /><br />w = 6<br /><br />Now that we have the width, we can find the length by multiplying the width by 5:<br /><br />Length = 5w = 5 × 6 = 30<br /><br />Now that we have the length and width, we can calculate the perimeter of the rectangle. The formula for the perimeter of a rectangle is 2 × (length + width). Substituting the values we found:<br /><br />Perimeter = 2 × (30 + 6) = 2 × 36 = 72<br /><br />Therefore, the perimeter of the rectangle is 72 yards.
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