Pergunta
Calade 4=(9)/(4)div (11)/(4) :8=(15)/(7)-(8)/(7) C=(5)/(8)+(8)/(7) :D=(5.3)/(7)+(8)/(8);E=(2.5)/(3)+(3.8)/(7);F=(0.1)/(3)-(27)/(9) G=(52)/(4)-(31)/(8) : H=(53)/(63)-(7)/(9) I=(43)/(43)+(1.3)/(24);J=(4)/(9)times (3)/(5);K=(4)/(9)times (3.5)/(5.2);1=(4.5)/(9)times (3)/(3.4) M=(2.2)/(54)times (3.3)/(7) :N=(22)/(7)times (15.4)/(5) Q=(7)/(9)div (3.2)/(5) :P=(10)/(84)div (3.1)/(0.5) : Q=(15.2)/(25)div (41)/(45)
Solução
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DiegoVeterano · Tutor por 9 anos
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$4=\frac {9}{4}\div \frac {11}{4}\quad :8=\frac {15}{7}-\frac {8}{7}$<br />$C=\frac {5}{8}+\frac {8}{7}\quad :D=\frac {5.3}{7}+\frac {8}{8};E=\frac {2.5}{3}+\frac {3.8}{7};F=\frac {0.1}{3}-\frac {27}{9}$<br />$G=\frac {52}{4}-\frac {31}{8}\quad :\quad H=\frac {53}{63}-\frac {7}{9}$<br />$I=\frac {43}{43}+\frac {1.3}{24};J=\frac {4}{9}\times \frac {3}{5};K=\frac {4}{9}\times \frac {3.5}{5.2};1=\frac {4.5}{9}\times \frac {3}{3.4}$<br />$M=\frac {2.2}{54}\times \frac {3.3}{7}\quad :N=\frac {22}{7}\times \frac {15.4}{5}$ $Q=\frac {7}{9}\div \frac {3.2}{5}\quad :P=\frac {10}{84}\div \frac {3.1}{0.5}\quad :\quad Q=\frac {15.2}{25}\div \frac {41}{45}$
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