Solve using elimination. -x+3y=19 3x-6y=-18 (II square square D

To solve the system of equations using elimination, we can follow these steps:

1. Multiply the first equation by 3 to make the coefficients of x in both equations equal:
$$-3x + 9y = 57$$

2. Add the two equations together to eliminate x:
$$-3x + 9y + 3x - 6y = 57 - 18$$
$$3y = 39$$

3. Solve for y:
$$y = 13$$

4. Substitute the value of y into one of the original equations to solve for x:
$$-x + 3(13) = 19$$
$$-x + 39 = 19$$
$$-x = -20$$
$$x = 20$$

Therefore, the solution to the system of equations is $$x = 20$$ and $$y = 13$$ .