Multiply: (6x^2-x)(2x+3)(2x^2-2) a 24x^5-32x^4+30x^3+32x^2-6x b 24x^5+32x^4-30x^3-32x^2+6x C 24x^5-32x^4-30x^3+32x^2-6x d 24x^5+32x^4+30x^3-32x^2-6x

To solve this problem, we need to multiply the given polynomials step by step.<br /><br />Given expression: $(6x^{2}-x)(2x+3)(2x^{2}-2)$<br /><br />Step 1: Multiply the first two polynomials:<br />$(6x^{2}-x)(2x+3) = 12x^{3} + 18x^{2} - 2x^{2} - 3x = 12x^{3} + 16x^{2} - 3x$<br /><br />Step 2: Multiply the result from step 1 with the third polynomial:<br />$(12x^{3} + 16x^{2} - 3x)(2x^{2}-2) = 24x^{5} + 32x^{4} - 6x^{3} - 24x^{3} - 32x^{2} + 6x = 24x^{5} + 32x^{4} - 30x^{3} - 32x^{2} + 6x$<br /><br />Therefore, the correct answer is option b: $24x^{5}+32x^{4}-30x^{3}-32x^{2}+6x$.