1)) Simplify Write your answer using whole numbers and variables. (4z^2-19z+12)/(4z^2)+21z-18 square

To simplify the given expression, we need to factorize both the numerator and the denominator.<br /><br />The numerator is $4z^{2}-19z+12$. We can factorize it as $(4z-3)(z-4)$.<br /><br />The denominator is $4z^{2}+21z-18$. We can factorize it as $(4z-3)(z+6)$.<br /><br />Now, we can rewrite the given expression as:<br /><br />$\frac{(4z-3)(z-4)}{(4z-3)(z+6)}$<br /><br />We can cancel out the common factor $(4z-3)$ from the numerator and denominator:<br /><br />$\frac{z-4}{z+6}$<br /><br />Therefore, the simplified form of the given expression is $\frac{z-4}{z+6}$.