Question 6 of 10 What is the vertex of the graph of the function below? y=x^2-4x+3 A. (1,0) B. (1,-1) C. (R,-1) D. (2,0)

To find the vertex of the quadratic function $y = x^2 - 4x + 3$, we can use the vertex formula for a parabola in the form $y = ax^2 + bx + c$, which is given by:<br /><br />\[ \text{Vertex} = \left( \frac{-b}{2a}, f\left(\frac{-b}{2a}\right) \right) \]<br /><br />For the given function $y = x^2 - 4x + 3$, we have:<br />- $a = 1$<br />- $b = -4$<br />- $c = 3$<br /><br />First, calculate the x-coordinate of the vertex:<br />\[ x = \frac{-(-4)}{2(1)} = \frac{4}{2} = 2 \]<br /><br />Next, substitute $x = 2$ back into the function to find the y-coordinate:<br />\[ y = (2)^2 - 4(2) + 3 = 4 - 8 + 3 = -1 \]<br /><br />Therefore, the vertex of the function is:<br />\[ (2, -1) \]<br /><br />So, the correct answer is:<br />D. $(2,0)$