Question 13(Multiple Choice Worth 2 points) (Polygon Angle Sums MC) A regular polygon has 12 sides. If one of its angles measures (8h-30)^circ what is the value of h? h=10.75 h=18.75 h=20.25 h=22.5

## Step 1<br />The sum of the interior angles of a polygon with \(n\) sides is given by the formula \((n-2) \times 180^{\circ}\). For a regular polygon, all angles are equal, so each angle is \(\frac{(n-2) \times 180^{\circ}}{n}\).<br /><br />## Step 2<br />In this case, the polygon has 12 sides, so each angle is \(\frac{(12-2) \times 180^{\circ}}{12} = 150^{\circ}\).<br /><br />## Step 3<br />Given that one of the angles measures \((830)^{\circ}\), we can set this equal to 150 and solve for \(h\):<br /><br />### \(8h - 30 = 150\)<br /><br />## Step 4<br />Adding 30 to both sides gives:<br /><br />### \(8h = 180\)<br /><br />## Step 5<br />Dividing both sides by 8 gives:<br /><br />### \(h = 22.5\)<br /><br />So, the value of \(h\) is 22.5.