6) f(n)=-4n+5 g(n)=2n-4 Find (fcirc g)(n)

To find $(f\circ g)(n)$, we need to substitute $g(n)$ into $f(n)$.<br /><br />Given:<br />$f(n)=-4n+5$<br />$g(n)=2n-4$<br /><br />Substitute $g(n)$ into $f(n)$:<br />$(f\circ g)(n) = f(g(n)) = f(2n-4)$<br /><br />Now, substitute $2n-4$ into $f(n)$:<br />$(f\circ g)(n) = -4(2n-4) + 5$<br /><br />Simplify the expression:<br />$(f\circ g)(n) = -8n + 16 + 5$<br />$(f\circ g)(n) = -8n + 21$<br /><br />Therefore, $(f\circ g)(n) = -8n + 21$.