What is the intermediate step in the form (x+a)^2=b as a result of completing the square for the following equation? x^2=-2x+63 Answer Attemptiout of 2 (2) (square )^2=

To complete the square for the equation \(x^2 = -2x + 63\), we need to follow these steps:<br /><br />1. Move the constant term to the other side of the equation:<br /> \[<br /> x^2 + 2x = 63<br /> \]<br /><br />2. To complete the square, take half of the coefficient of \(x\), which is 2, divide it by 2 to get 1, and then square it to get 1. Add this square to both sides of the equation:<br /> \[<br /> x^2 + 2x + 1 = 63 + 1<br /> \]<br /><br />3. Simplify the equation:<br /> \[<br /> x^2 + 2x + 1 = 64<br /> \]<br /><br />4. The left side of the equation can now be written as a perfect square:<br /> \[<br /> (x + 1)^2 = 64<br /> \]<br /><br />So, the intermediate step in the form \((x + a)^2 = b\) is:<br />\[<br />(x + 1)^2 = 64<br />\]