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a) 2 x+4=6 0-4 x=-16 g) -2 y=0 h) 3 y+1=10

Pergunta

a) 2 x+4=6 
 0-4 x=-16 
g) -2 y=0 
h) 3 y+1=10

a) 2 x+4=6 0-4 x=-16 g) -2 y=0 h) 3 y+1=10

Solução

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JéssicaElite · Tutor por 8 anos

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Let's solve each equation step by step:<br /><br />a) \( 2x + 4 = 6 \)<br /><br />To solve for \( x \), we need to isolate \( x \) on one side of the equation. We can do this by subtracting 4 from both sides of the equation:<br /><br />\[ 2x + 4 - 4 = 6 - 4 \]<br /><br />This simplifies to:<br /><br />\[ 2x = 2 \]<br /><br />Next, we divide both sides by 2:<br /><br />\[ \frac{2x}{2} = \frac{2}{2} \]<br /><br />This simplifies to:<br /><br />\[ x = 1 \]<br /><br />So, the solution to the equation \( 2x + 4 = 6 \) is \( x = 1 \).<br /><br />b) \( 0 - 4x = -16 \)<br /><br />To solve for \( x \), we need to isolate \( x \) on one side of the equation. We can do this by dividing both sides by -4:<br /><br />\[ \frac{0 - 4x}{-4} = \frac{-16}{-4} \]<br /><br />This simplifies to:<br /><br />\[ x = 4 \]<br /><br />So, the solution to the equation \( 0 - 4x = -16 \) is \( x = 4 \).<br /><br />g) \( -2y = 0 \)<br /><br />To solve for \( y \), we need to isolate \( y \) on one side of the equation. We can do this by dividing both sides by -2:<br /><br />\[ \frac{-2y}{-2} = \frac{0}{-2} \]<br /><br />This simplifies to:<br /><br />\[ y = 0 \]<br /><br />So, the solution to the equation \( -2y = 0 \) is \( y = 0 \).<br /><br />h) \( 3y + 1 = 10 \)<br /><br />To solve for \( y \), we need to isolate \( y \) on one side of the equation. We can do this by subtracting 1 from both sides of the equation:<br /><br />\[ 3y + 1 - 1 = 10 - 1 \]<br /><br />This simplifies to:<br /><br />\[ 3y = 9 \]<br /><br />Next, we divide both sides by 3:<br /><br />\[ \frac{3y}{3} = \frac{9}{3} \]<br /><br />This simplifies to:<br /><br />\[ y = 3 \]<br /><br />So, the solution to the equation \( 3y + 1 = 10 \) is \( y = 3 \).
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