An artist advertises an enlarged model of a scorpionfly. The scale of the model to the original is 36:1 , and the model has an enlarged width of 1170 millimeters. Assuming these measurements are accurate, how wide was the original scorpionfly, in millimeters? square

To find the width of the original sc factor is 36:1, which means that every 36 millimeters in the model corresponds to 1 millimeter in the original scorpionfly.<br /><br />Given:<br />- Enlarged width of the model = 1170 millimeters<br />- Scale factor = 36:1<br /><br />We can set up a proportion to find the width of the original scorpionfly:<br /><br />\[<br />\frac{\text{Enlarged width of the model}}{\text{Width of the original scorpionfly}} = \frac{36}{1}<br />\]<br /><br />Let \( x \) be the width of the original scorpionfly. Then we have:<br /><br />\[<br />\frac{1170}{x} = 36<br />\]<br /><br />To solve for \( x \), we can cross-multiply:<br /><br />\[<br />1170 = 36x<br />\]<br /><br />Now, divide both sides by 36:<br /><br />\[<br />x = \frac{1170}{36}<br />\]<br /><br />Simplify the fraction:<br /><br />\[<br />x = 32.5<br />\]<br /><br />Therefore, the width of the original scorpionfly was 32.5 millimeters.