Pergunta

f) (-3)^-2 k) -((2)/(5))^-2 p) (0,75)^-2 g) -5^-2 1) -(-(2)/(3))^-3 q) (1)/(2^-3) h) ((1)/(3))^-2 m) (0,1)^-2 r) (1)/((0,2)^-2) -1 i) ((2)/(3))^-1 n) (0,25)^-3 s) (1)/((-3)^-3) j) (-(3)/(2))^-3 0) (-0,5)^-3 t) (1)/((0,01)^-2)
Solução

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KiaraElite · Tutor por 8 anos
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f) (-3)^{-2} = \frac{1}{(-3)^2} = \frac{1}{9}
k) -(\frac{2}{5})^{-2} = -(\frac{5}{2})^2 = -\frac{25}{4}
p) (0,75)^{-2} = (\frac{3}{4})^2 = \frac{9}{16}
g) -5^{-2} = -\frac{1}{5^2} = -\frac{1}{25}
1) -(-\frac{2}{3})^{-3} = -(-\frac{3}{2})^3 = -\frac{27}{8}
q) \frac{1}{2^{-3}} = 2^3 = 8
h) (\frac{1}{3})^{-2} = 3^2 = 9
m) (0,1)^{-2} = 10^2 = 100
r) \frac{1}{(0,2)^{-2}} = (0,2)^2 = 0,04
i) (\frac{2}{3})^{-1} = \frac{3}{2}
n) (0,25)^{-3} = 4^3 = 64
s) \frac{1}{(-3)^{-3}} = (-3)^3 = -27
j) (-\frac{3}{2})^{-3} = (-\frac{2}{3})^3 = -\frac{8}{27}
0) (-0,5)^{-3} = (-2)^3 = -8
t) \frac{1}{(0,01)^{-2}} = (0,01)^2 = 0,0001
k) -(\frac{2}{5})^{-2} = -(\frac{5}{2})^2 = -\frac{25}{4}
p) (0,75)^{-2} = (\frac{3}{4})^2 = \frac{9}{16}
g) -5^{-2} = -\frac{1}{5^2} = -\frac{1}{25}
1) -(-\frac{2}{3})^{-3} = -(-\frac{3}{2})^3 = -\frac{27}{8}
q) \frac{1}{2^{-3}} = 2^3 = 8
h) (\frac{1}{3})^{-2} = 3^2 = 9
m) (0,1)^{-2} = 10^2 = 100
r) \frac{1}{(0,2)^{-2}} = (0,2)^2 = 0,04
i) (\frac{2}{3})^{-1} = \frac{3}{2}
n) (0,25)^{-3} = 4^3 = 64
s) \frac{1}{(-3)^{-3}} = (-3)^3 = -27
j) (-\frac{3}{2})^{-3} = (-\frac{2}{3})^3 = -\frac{8}{27}
0) (-0,5)^{-3} = (-2)^3 = -8
t) \frac{1}{(0,01)^{-2}} = (0,01)^2 = 0,0001
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