Pergunta

Find the distance between (3,-5) and (-4,10) on the xy -plane.
Solução

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AntoniMestre · Tutor por 5 anos
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The distance between the points (3,-5) and (-4,10) on the xy-plane is 13 \sqrt{2}.
Explicação
## Step 1
The problem asks us to find the distance between two points on the xy-plane. The formula to find the distance between two points (x_1, y_1) and (x_2, y_2) on the xy-plane is given by:
### \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}
## Step 2
Substitute the given points (3,-5) and (-4,10) into the formula. This gives us:
### \sqrt{(-4 - 3)^2 + (10 - (-5))^2}
## Step 3
Simplify the expression inside the square root:
### \sqrt{49 + 225}
## Step 4
Add the numbers inside the square root:
### \sqrt{274}
## Step 5
The square root of 274 can be simplified to 13 \sqrt{2}.
The problem asks us to find the distance between two points on the xy-plane. The formula to find the distance between two points (x_1, y_1) and (x_2, y_2) on the xy-plane is given by:
### \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}
## Step 2
Substitute the given points (3,-5) and (-4,10) into the formula. This gives us:
### \sqrt{(-4 - 3)^2 + (10 - (-5))^2}
## Step 3
Simplify the expression inside the square root:
### \sqrt{49 + 225}
## Step 4
Add the numbers inside the square root:
### \sqrt{274}
## Step 5
The square root of 274 can be simplified to 13 \sqrt{2}.
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