11. 1x=-3 13. y=6x+1 15. y=(1)/(5)x

11. To solve the equation $1x = -3$, we need to isolate the variable $x$. <br /><br />Dividing both sides of the equation by 1, we get:<br /><br />$x = -3$<br /><br />Therefore, the solution to the equation is $x = -3$.<br /><br />13. The equation $y = 6x + 1$ is already in the form of a linear equation. It represents a straight line with a slope of 6 and a y-intercept of 1.<br /><br />To find the value of $y$ for a given value of $x$, we can substitute the value of $x$ into the equation and solve for $y$.<br /><br />For example, if $x = 2$, we can substitute it into the equation:<br /><br />$y = 6(2) + 1$<br /><br />Simplifying the equation, we get:<br /><br />$y = 12 + 1$<br /><br />$y = 13$<br /><br />Therefore, when $x = 2$, the value of $y$ is 13.<br /><br />15. The equation $y = \frac{1}{5}x$ is also in the form of a linear equation. It represents a straight line with a slope of $\frac{1}{5}$ and a y-intercept of 0.<br /><br />To find the value of $y$ for a given value of $x$, we can substitute the value of $x$ into the equation and solve for $y$.<br /><br />For example, if $x = 10$, we can substitute it into the equation:<br /><br />$y = \frac{1}{5}(10)$<br /><br />Simplifying the equation, we get:<br /><br />$y = 2$<br /><br />Therefore, when $x = 10$, the value of $y$ is 2.