Find the quotlent. (8a^4-16a^2-a)div 2a^2 A) 4a^2-8-(1)/(2a) 4a^2+8+(1)/(2a) 4a^2-8-(a)/(2) 4a^4-8a^2-(1)/(2)a

To find the quotient, we need to divide each term in the numerator by the denominator.<br /><br />Step 1: Divide the first term in the numerator by the denominator.<br />\[\frac{8a^{4}}{2a^{2}} = 4a^{2}\]<br /><br />Step 2: Divide the second term in the numerator by the denominator.<br />\[\frac{-16a^{2}}{2a^{2}} = -8\]<br /><br />Step 3: Divide the third term in the numerator by the denominator.<br />\[\frac{-a}{2a^{2}} = -\frac{1}{2a}\]<br /><br />Putting it all together, the quotient is:<br />\[4a^{2}-8-\frac {1}{2a}\]<br /><br />Therefore, the correct answer is:<br />A) $4a^{2}-8-\frac {1}{2a}$