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89| Calcule as potências. a) ((4)/(9))^2= ((1)/(5))^4= ((7)/(4))^3= d) ((8)/(5))^2= e) ((1)/(3))^0= f) ((1)/(2))^1=

Pergunta

89| Calcule as potências.
a) ((4)/(9))^2= ((1)/(5))^4= ((7)/(4))^3=
d) ((8)/(5))^2= e) ((1)/(3))^0= f) ((1)/(2))^1=

89| Calcule as potências. a) ((4)/(9))^2= ((1)/(5))^4= ((7)/(4))^3= d) ((8)/(5))^2= e) ((1)/(3))^0= f) ((1)/(2))^1=

Solução

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Alice MariaElite · Tutor por 8 anos

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Vamos calcular as potências fornecidas:<br /><br />a) \((\frac{4}{9})^{2}\):<br />\[<br />(\frac{4}{9})^{2} = \frac{4^2}{9^2} = \frac{16}{81}<br />\]<br /><br />b) \((\frac{1}{5})^{4}\):<br />\[<br />(\frac{1}{5})^{4} = \frac{1^4}{5^4} = \frac{1}{625}<br />\]<br /><br />c) \((\frac{7}{4})^{3}\):<br />\[<br />(\frac{7}{4})^{3} = \frac{7^3}{4^3} = \frac{343}{64}<br />\]<br /><br />d) \((\frac{8}{5})^{2}\):<br />\[<br />(\frac{8}{5})^{2} = \frac{8^2}{5^2} = \frac{64}{25}<br />\]<br /><br />e) \((\frac{1}{3})^{0}\):<br />\[<br />(\frac{1}{3})^{0} = 1<br />\]<br /><br />f) \((\frac{1}{2})^{1}\):<br />\[<br />(\frac{1}{2})^{1} = \frac{1}{2}<br />\]<br /><br />Portanto, as potências calculadas são:<br /><br />a) \((\frac{4}{9})^{2} = \frac{16}{81}\)<br /><br />b) \((\frac{1}{5})^{4} = \frac{1}{625}\)<br /><br />c) \((\frac{7}{4})^{3} = \frac{343}{64}\)<br /><br />d) \((\frac{8}{5})^{2} = \frac{64}{25}\)<br /><br />e) \((\frac{1}{3})^{0} = 1\)<br /><br />f) \((\frac{1}{2})^{1} = \frac{1}{2}\)
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