1. Determine o valor numérico de cada expressão para a=(1)/(2) e b=(1)/(8) (1) a-b= (2) b-a= (3) -(a-b)= (4) -(b-a)= (5) (a-b)^2=((1)/(2)-(1)/(8))^2= (6) (b-a)^2= (7) -(a-b)^2= (8) -(b-a)^2= (9) -(-a+b)^2=

Vamos calcular o valor numérico de cada expressão para \(a=\frac{1}{2}\) e \(b=\frac{1}{8}\):<br /><br />(1) \(a - b = \frac{1}{2} - \frac{1}{8} = \frac{4}{8} - \frac{1}{8} = \frac{3}{8}\)<br /><br />(2) \(b - a = \frac{1}{8} - \frac{1}{2} = \frac{1}{8} - \frac{4}{8} = -\frac{3}{8}\)<br /><br />(3) \(-(a - b) = -\left(\frac{1}{2} - \frac{1}{8}\right) = -\left(\frac{4}{8} - \frac{1}{8}\right) = -\left(\frac{3}{8}\right) = -\frac{3}{8}\)<br /><br />(4) \(-(b - a) = -\left(\frac{1}{8} - \frac{1}{2}\right) = -\left(\frac{1}{8} - \frac{4}{8}\right) = -\left(-\frac{3}{8}\right) = \frac{3}{8}\)<br /><br />(5) \((a - b)^2 = \left(\frac{1}{2} - \frac{1}{8}\right)^2 = \left(\frac{4}{8} - \frac{1}{8}\right)^2 = \left(\frac{3}{8}\right)^2 = \frac{9}{64}\)<br /><br />(6) \((b - a)^2 = \left(\frac{1}{8} - \frac{1}{2}\right)^2 = \left(\frac{1}{8} - \frac{4}{8}\right)^2 = \left(-\frac{3}{8}\right)^2 = \frac{9}{64}\)<br /><br />(7) \(-(a - b)^2 = -\left(\frac{1}{2} - \frac{1}{8}\right)^2 = -\left(\frac{3}{8}\right)^2 = -\frac{9}{64}\)<br /><br />(8) \(-(b - a)^2 = -\left(\frac{1}{8} - \frac{1}{2}\right)^2 = -\left(-\frac{3}{8}\right)^2 = -\frac{9}{64}\)<br /><br />(9) \(-(-a + b)^2 = -\left(-\frac{1}{2} + \frac{1}{8}\right)^2 = -\left(-\frac{4}{8} + \frac{1}{8}\right)^2 = -\left(-\frac{3}{8}\right)^2 = -\frac{9}{64}\)<br /><br />Portanto, os valores numéricos das expressões são:<br /><br />(1) \(\frac{3}{8}\)<br /><br />(2) \(-\frac{3}{8}\)<br /><br />(3) \(-\frac{3}{8}\)<br /><br />(4) \(\frac{3}{8}\)<br /><br />(5) \(\frac{9}{64}\)<br /><br />(6) \(\frac{9}{64}\)<br /><br />(7) \(-\frac{9}{64}\)<br /><br />(8) \(-\frac{9}{64}\)<br /><br />(9) \(-\frac{9}{64}\)